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Enabled single-file generation #1

Enabled single-file generation

Enabled single-file generation #1

Triggered via pull request August 15, 2025 13:52
Status Failure
Total duration 37s
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pr.yml

on: pull_request
build-test-format
33s
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5 errors
build-test-format
Process completed with exit code 1.
build-test-format: src/DataverseProxyGenerator.Core/Generation/Generators/CustomApiGenerator.cs#L9
In member IEnumerable<GeneratedFile> CustomApiGenerator.Generate(CustomApiModel customApi, GenerationContext context), change parameter name customApi to input in order to match the identifier as it has been declared in IEnumerable<GeneratedFile> IFileGenerator<CustomApiModel>.Generate(CustomApiModel input, GenerationContext context) (https://learn.microsoft.com/dotnet/fundamentals/code-analysis/quality-rules/ca1725)
build-test-format: src/DataverseProxyGenerator.Core/Generation/Generators/HelperFileGenerator.cs#L9
In member IEnumerable<GeneratedFile> HelperFileGenerator.Generate(string templateName, GenerationContext context), change parameter name templateName to input in order to match the identifier as it has been declared in IEnumerable<GeneratedFile> IFileGenerator<string>.Generate(string input, GenerationContext context) (https://learn.microsoft.com/dotnet/fundamentals/code-analysis/quality-rules/ca1725)
build-test-format: src/DataverseProxyGenerator.Core/Generation/Generators/CustomApiGenerator.cs#L9
In member IEnumerable<GeneratedFile> CustomApiGenerator.Generate(CustomApiModel customApi, GenerationContext context), change parameter name customApi to input in order to match the identifier as it has been declared in IEnumerable<GeneratedFile> IFileGenerator<CustomApiModel>.Generate(CustomApiModel input, GenerationContext context) (https://learn.microsoft.com/dotnet/fundamentals/code-analysis/quality-rules/ca1725)
build-test-format: src/DataverseProxyGenerator.Core/Generation/Generators/HelperFileGenerator.cs#L9
In member IEnumerable<GeneratedFile> HelperFileGenerator.Generate(string templateName, GenerationContext context), change parameter name templateName to input in order to match the identifier as it has been declared in IEnumerable<GeneratedFile> IFileGenerator<string>.Generate(string input, GenerationContext context) (https://learn.microsoft.com/dotnet/fundamentals/code-analysis/quality-rules/ca1725)