fix: generic type of graph argument accept any LinkProps in findNodes, getNode, getFirstNode

Author: JesusTheHun

src/utils/findNodes.ts

@@ -5,7 +5,7 @@ import { NoInfer } from '../types.js';
  * Returns all the nodes matching your function.
  */
 export function findNodes<Node>(
-  graph: Graph<Node>,
+  graph: Graph<Node, any>,
   fn: (node: NoInfer<Node>) => boolean,
 ): Node[] {
   const nodes: Node[] = [];

src/utils/getFirstNode.ts

@@ -5,7 +5,7 @@ import { NoInfer } from '../types.js';
  * Return the first node matching your function and throws if none is found.
  */
 export function getFirstNode<Node>(
-  graph: Graph<Node>,
+  graph: Graph<Node, any>,
   fn: (node: NoInfer<Node>) => boolean,
 ): Node {
   for (const node of graph.nodes) {

src/utils/getNode.spec.ts

@@ -32,4 +32,13 @@ describe('getNode', () => {
 
     expect(() => getNode(graph, (n) => n.type === 'foo')).toThrowError();
   });
+
+  it.skip('should not trigger a type error when the link props are set', ({ expect }) => {
+    const graph = new Graph<Node, { foo: string }>();
+    const node1 = { id: '1', type: 'foo' };
+
+    graph.addNode(node1);
+
+    expect(getNode(graph, (n) => n.id === '1')).toEqual(node1);
+  });
 });

src/utils/getNode.ts

@@ -5,7 +5,7 @@ import { NoInfer } from '../types.js';
  * Return the node matching your function. Throws if none is found or if more than one node if found.
  */
 export function getNode<Node>(
-  graph: Graph<Node>,
+  graph: Graph<Node, any>,
   fn: (node: NoInfer<Node>) => boolean,
 ): Node {
   const foundNodes: Node[] = [];